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x=-4x^2+46x-126
We move all terms to the left:
x-(-4x^2+46x-126)=0
We get rid of parentheses
4x^2-46x+x+126=0
We add all the numbers together, and all the variables
4x^2-45x+126=0
a = 4; b = -45; c = +126;
Δ = b2-4ac
Δ = -452-4·4·126
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-3}{2*4}=\frac{42}{8} =5+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+3}{2*4}=\frac{48}{8} =6 $
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